Mob Aggro v179.1

anyone know how to update mob aggro scripts? i know how to update AOB but dont know how to find the offset part

Aggro:
mov eax,[01568B62] //Char Base 8B 3D ? ? ? ? 8B CF F3
lea eax,[eax+04]
mov [ecx+000004D0+08],eax //Aggro offset 83 BE ? ? ? ? 00 0F 85 ? ? 00 00 8B CE E8 ? ? ? ? 85 C0 74 [Offset+0x08]

push ebp
mov ebp,esp
push -01
jmp return

122B68E9:
jmp Aggro
return:


[DISABLE]
122B68E9:// CVecCtrlMob::WorkUpdateActive: E9 ? ? ? ? 8B ? ? ? 00 00 83 ? ? 0F ? ? ? ? ? FF
push ebp
mov ebp,esp
push -01


dealloc(Aggro)

 

Code:

[Enable]
Alloc(Aggro, 128)
Label(return)

Aggro:
mov eax,[03341D90] //Char Base 8B 3D ? ? ? ? 8B CF F3
lea eax,[eax+04]
mov [ecx+000004D0+08],eax //Aggro offset 83 BE ? ? ? ? 00 0F 85 ? ? 00 00 8B CE E8 ? ? ? ? 85 C0 74 [Offset+0x08]

push ebp
mov ebp,esp
push -01
jmp return

026559A0:
jmp Aggro
return:


[DISABLE]
026559A0:// CVecCtrlMob::WorkUpdateActive: E9 ? ? ? ? 8B ? ? ? 00 00 83 ? ? 0F ? ? ? ? ? FF
push ebp
mov ebp,esp
push -01


dealloc(Aggro)

 

Nice job with the correct addresses.

The aggro offset is still wrong though... I'm referring to the ecx+000004D0+08

But... I found the working aggro offset. It's ecx+4D8

So just copy this below ^_^

Code:

[ENABLE]
alloc(Aggro,128)
label(return)

Aggro:
mov eax,[03341D90] //Char Base 8B 3D ? ? ? ?  8B CF F3
lea eax,[eax+04]
mov [ecx+4D8],eax //Aggro offset 83 BE ? ? ? ? 00 0F 85 ? ? 00 00 8B CE E8 ? ? ? ? 85 C0 74 [Offset+0x08]

push ebp
mov ebp,esp
push -01
jmp return

026559A0:
jmp Aggro
return:


[DISABLE]
026559A0:// CVecCtrlMob::WorkUpdateActive: E9 ? ? ? ? 8B ? ? ? 00 00 83 ? ? 0F ? ? ? ? ? FF
push ebp
mov ebp,esp
push -01


dealloc(Aggro)

 

Nice job. But did u ever try out mine. 4D0+0x08 = 4D8

 

worked. thanks

 

Yea I tried your original. Not sure why, it could turn on and off for me, but had no effect. But your addresses were helpful!

But thanks, I didn't know can add and multiply the offset like that. I'm a complete newbie haha

 

Becuz my return was spelled as Return probably

 

how you got the address 026559A0? i already do so many research still cant get this address...can you teach me how to find it?